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-4w^2+36=0
a = -4; b = 0; c = +36;
Δ = b2-4ac
Δ = 02-4·(-4)·36
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24}{2*-4}=\frac{-24}{-8} =+3 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24}{2*-4}=\frac{24}{-8} =-3 $
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